x = -3±5i (remember complex numbers come in conjugates)
(x+3)2 = -25
x2+6x+9 = -25
x2+6x+34 = 0
x = 4±√6 (also a conjugate pair here)
(x-4)2 = 6
x2-8x+16 = 6
x2-8x+10 = 0
(x2+6x+34)(x2-8x+10) = x4-8x3+10x2+6x3-48x2+60x+34x2-272x+340 = x4-2x3-4x2-212x+340
f(x) = x4-2x3-4x2-212x+340
f(1) = 14-2(1)3-4(1)2-212(1)+340 = 123
Since 246 is twice as big as 123, we can simply multiply the function by 2 and get our final answer:
f(x) = 2x4-4x3-8x2-424x+680
Hope this helped!