I'm stuck on a question

Question

According to the reaction below, how many moles of Cu₂CO₃(s) can be produced from 125 mL of 0.198 M CuNO₃(aq)? Assume that there is excess Li₂CO₃(aq).

2 CuNO₃(aq) + Li₂CO₃(aq) → Cu₂CO₃(s) + 2 LiNO₃(aq)

Answer 1

Where to start:

Identify what you're looking for:

moles Cu₂CO₃ = ?

Identify given

125 mL CuNO₃

0.198 M CuNO₃

You can convert from one compound to another using mole-to-mole conversion and coefficients from the balanced equation. Since we don't have moles for CuNO₃ we can use the Molarity formula to solve for moles. M = moles/Liters (convert mL → L)

Solve for moles of CuNO₃

0.198 = moles / 0.125 L

moles = 0.02475

Convert moles of CuNO₃ to moles Cu₂CO₃

0.02475 mol CuNO₃ x (1 mol Cu₂CO₃/ 2 mol CuNO₃) = 0.0124 mol Cu₂CO₃ - ANSWER

CuNO₃ has a coefficient of 1 and CuNO₃ has a coefficient of 2 in the equation.

When using the conversion factor, the unit you want to cancel out should be across from one another. ex: mol of CuNO₃ is on the top and on the bottom so they cancel out.