The specific heat capacity of lead is 0.13 J/g oC. How much heat (in J) is required to raise the temperature of 12.6 g of lead from 28.3°C to 36.3°C? Keep three significant figures in your answer.

Question

The specific heat capacity of lead is 0.13 J/g ^oC. How much heat (in J) is required to raise the temperature of 12.6 g of lead from 28.3°C to 36.3°C? Keep three significant figures in your answer. 

Answer 1

Hi Logan. Thank you for posting this awesome question!

Given the specific heat capacity of lead, 0.13 J/gC , the mass of lead, 12.6g, and the temperature change of 36.3C-28.3C (=8.00C keeping 3 decimal points for the 3 significant figures in answer), you can find the heat (q) absorbed with the equation, q = mcΔT, by plugging in the given values.