f(x) = x3 + 4x - 5
f'(x) = 3x2 + 4
f'(x) > 0 for all x
So, f is increasing on (-∞, ∞)
f is never decreasing
Since the function is differentiable for all x and the derivative does not change sign, there are no relative extrema.
Sam J.
asked 03/23/15
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