
Yefim S. answered 12/21/22
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dy/y2 = dx/x2; ∫dy/y2 = ∫dx/x2; - 1/y = - 1/x - C; x = y + Cxy; y = x/(1 + Cx)
Aznan M.
asked 12/21/22Solve the following homogenous equation x^2 dy/dx = y^2. Please help me, thank you sir.
Yefim S. answered 12/21/22
Math Tutor with Experience
dy/y2 = dx/x2; ∫dy/y2 = ∫dx/x2; - 1/y = - 1/x - C; x = y + Cxy; y = x/(1 + Cx)
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