Let x = width. Then length = 7x - 18.
x(7x - 18) = 405
7x2 - 18x - 405 = 0
(7x + 45)(x - 9) = 0
Solve for x.
Yaireth L.
asked 12/05/22A rectangle has a length of 18 feet less than 7 times it’s width. If the area of the rectangle is 405 square feet, find the length of the rectangle
Let x = width. Then length = 7x - 18.
x(7x - 18) = 405
7x2 - 18x - 405 = 0
(7x + 45)(x - 9) = 0
Solve for x.
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