Draw the situation out. Let's call the width of the frame x.
The area of the frame will be x(2(L+2x) + 2W) from the sum of the rectangular areas formed.
The areas being equal means that this area is 150 in2
Subbing in for L and W (It doesn't matter which is which)
x(2(15+2x)+20) = 150
x(50 + 4x) = 150
4x2 + 50x -150 = 0
Use quadratic formula: x = 5/2
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