Use differentials and the graph of g' to approximate g(2.99) and g(3.2) given that g(3) = 3. g(2.99) ≈ 3.01 Correct: Your answer is correct. g(3.2) ≈ 2.99 Incorrect: Your answer is incorrect.

Question

Use differentials and the graph of g' to approximate g(2.99) and g(3.2) given that g(3) = 3.

g(2.99) ≈  

g(3.2)=

Answer 1

g(2.99) = g(3) + g'(3)(2.99 - 3) = 3 + 3(- 0.01) = 2.97

g(3.2) = 9(3) + g'(3)(3.2 - 3) = 3 + 3(0.2) = 3.6