
Yefim S. answered 10/13/22
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f(x, vx) = (x2 - k2x2)/(3x2k) = (1 - k2)/(3k);
Let y = vx, then dy/dx = y' = v'x + v; v'x + v = (1 - v2)/(3v); v'x = (1 - 4v2)/(3v)∫;
∫(3v)/(1 - 4v2)dv = ∫dx/x; - 3/8lnI1 - 4v2) = lnIxI + C
-3/8lnI1 - 4y2/x2I = lnIxI + C
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