If we call the numbers: (x, y, z), then: y = 2x and y = 3z. Also 44= (x+y+z)/3.
In other words, 44 = (y/2 + y + y/3) = 11y/6 , or y = 24. Therefore x=12 and z=8.
Now the difference x-z = 4.
ps. this is a simple algebra question and has nothing to do with differential equations as the question has been categorized.