Take common factors of 6 from the first factor and 3 from the 2nd factor.
The set u=x-x2+1, du = 1-2x.
Now you have an integral of the form u6 du.
Jasim C.
asked 05/05/22∫(6-12x)(3x-3x2+3)6 dx= ?
I'm stuck on this
Take common factors of 6 from the first factor and 3 from the 2nd factor.
The set u=x-x2+1, du = 1-2x.
Now you have an integral of the form u6 du.
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