Tom N. answered 05/05/22
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Strong proficiency in elementary and advanced mathematics
∫0∞e-ndn = -(e-n)0∞ = -e-∞ +1 = 1- 1/e∞ =1-0= 1 which establishes convergence.
Ana A.
asked 05/04/22Use the integral test to establish the convergence of the series which is the sum from n=1 to infinity of the terms an=e-n
Tom N. answered 05/05/22
Strong proficiency in elementary and advanced mathematics
∫0∞e-ndn = -(e-n)0∞ = -e-∞ +1 = 1- 1/e∞ =1-0= 1 which establishes convergence.
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