
Yefim S. answered 04/19/22
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∫-44f(x)dx = ∫-402dx + ∫04(4 - x2)dx = 2x-40 + (4x - x3/3)04 = 8 + 16 - 64/3 = 8/3
Kore C.
asked 04/18/22Evaluate the integral.
4 | f(x) dx | ||
![]() | |||
−4 | |||
where f(x) = ![]() |
2 | if | −4 ≤ x ≤ 0 |
4 − x2 | if | 0 < x ≤ 4 |
Yefim S. answered 04/19/22
Math Tutor with Experience
∫-44f(x)dx = ∫-402dx + ∫04(4 - x2)dx = 2x-40 + (4x - x3/3)04 = 8 + 16 - 64/3 = 8/3
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