Chemistry Calculaations

Question

Calculate the concentration of an aqueous KCl solution if 322 mL of the solution gives 13.1 g of AgCl when treated with excess AgNO ₃. The equation for the reaction is 

KCl( aq)    +    AgNO ₃( aq)     ---->     AgCl( s)    +    KNO ₃( aq)

Answer 1

The molar mass of AgCl is 143.32.

13.1 / 143.32 = 0.0914 mol

If AgNO3 was in excess, that means KCl is the limiting reactant, so the number of moles of the product should equal the number of moles of KCl (the mol-to-mol ratio of KCl to AgCl is 1-to-1).

0.0914 mol of KCl / 0.322 L = 0.284 M