
Eric G. answered 03/13/22
Experienced Organic Chemistry Tutor
So, Benzene is aromatic, which means it has a very unique type of resonance stability. In plain terms, those pi electrons of the double bonds are not as available to take part in the typical alkene reactions we are previously used to (i.e. adding H2O or Br2), making Benzene a very poor nucleophile due to the fact that it does not want to give up its aromaticity just to add a substituent. With that being said, if we have a poor nucleophile, we just "super charge" the electrophile (or we increase the positivity of the electrophile), making it more attractive to the weak nucleophile. By using a Lewis acid like AlCl3 or FeBr3, it makes a very strong electrophile (Cl+ or Br+) so that the Benzene is driven by this attraction to react. In your example specifically, the electrophile would be something like H3C-Cl+-Al-Cl3 or +CH3. (Note: I'm saying Cl+ and Br+ to simplify the complexes, in books it will be more like Cl-Cl+-Al-Cl3 and Br-Br+-Fe-Br3).