
Luke J. answered 09/02/23
Experienced High School through College STEM Tutor
If a point, say ( a, b ), were desired to pass thru the solution to the differential equation, then you'd solve for the constant of integration like so:
b = C * exp(-a/2)
Note: exp() and e^() are equivalent statements of the same function
b * exp(a/2) = C*exp(-a/2)*exp(a/2)
C = b * exp(a/2)
∴ y = b * exp( - ( x - a ) / 2 )
I hope this helps! Message me in the comments with any questions, comments, or concerns!