
Patrick C.
asked 02/15/22Draw and name the product of reduction from 2-ethyl-3,4-dimethyoctanal+H
Draw the structure and write the IUPAC name of the products
1 Expert Answer
Note that I don't know what is meant by the +H in the name. Also, a complete reduction of an aldehyde, like in the Wolff-Kishner reduction, is to an alkane, not an alcohol. This reduction is not usually taught this early in the semester, so I assumed it was a reduction to the alcohol. If it is the reduction to the alkane then the parent changes to a nonane, not an octane. Anyway, if it was supposed to be a complete reduction to the alkane let me know, and I can help you with that if needed.

Luke J.
I believe like you state in your video how "reduction in Organic Chemistry adds a hydrogen on either side of a double bond", I believe the student's note of ...octanal+H meant 1 step of reduction and not any further like you state that the Wolff-Kishner reduction would typically do. I don't know the student personally but that is my deduction in looking into your video and your well executed solution. Thank you, Nathan B!02/15/22
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Stanton D.
First, dimethy is not a IUPAC prefix. dimethyl, perhaps? Second, what's up with octanal+H ? Are we talking a charged molecule? Third, if you reduce an aldehyde completely, you (usually) get the terminal alcohol. What is the issue with naming that, you already have the substituents on and named properly? -- Cheers, --Mr. d.02/15/22