Integral of |sinx| dx with limits from 0 to minus pie

Answer 1

On the interval [0,-pi], the absolute sin function is equivalent to -sin(x).

integral(|sin(x)|,0,-pi) = integral(-sin(x),0,-pi)

We can integrate from -pi to 0 (left to right); just add a negative sign in the front.

= -integral(-sin(x), -pi, 0)

= integral(sin(x), -pi, 0)

= (-cos(0)) - (-cos(-pi))

= -1-1

= -2