
Jim E.
asked 12/27/21Diffrencial equation( Non-Exact)
(1+ cos(x))y' = (sin²(x)+sin²(x) cos(x)- ysin(x))
1 Expert Answer

Yefim S. answered 12/27/21
Math Tutor with Experience
y' - sinx/(1 + cosx)y = sin2x; Integrated factor M(x) = e∫-sinx/(1 + cosx)dx = 1 + cosx;
y'(1 + cosx) - ysinx = sin2x(1 + cosx); [y(1 + cosx)]' = sin2x(1 + cosx); y(1 + cosx) = ∫sin2x(1 + cosx)dx;
y(1 + cosx) = ∫[(1 - cos2x)/2 + sin2xcosx)dx; y(1 + cosx) = x/2 - sin2x/4 + sin3x/3 + C;
y = (x/2 - sin2x/4 + sin3x/3 + C)/(1 + cosx);
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Douglas B.
Please show what you have tried. If it's an almost exact equation, you basically have two different options for finding an integrating factor to make it exact. Once you make it exact, then you can solve it.12/27/21