Quifaren H.

asked • 12/13/21

Find the Percent yield

25.0 grams of chlorine reacts with 29.0 grams of sodium 2Na+Cl2→2NaCl The Percent yield?


Donna K.

HInt - convert grams to moles use molar ratio from coefficients to get product. Repeat for second reactant to find which gives LESS - that is the limiting reagent. Then take those grams and comare to the max possible (if there was enough of both reagents)
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12/23/21

1 Expert Answer

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Dr. Somashree K. answered • 01/01/22

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25 g of chlorine is equals to 25/71 =0.352 mole.

29 g of sodium is equals to 29/23=1.261 mole.


Sodium reacts with chlorine in 2:1 molar ratio.


So, 1 mole of Cl2 reacts with 2 mole of sodium.

i. e., 0.352 mole of Cl2 will react with 2×0.352 mole of sodium= 0.704 mole of sodium.


Since, sodium is present in excess, chlorine is the limiting reagent.


1 mole Cl2 produces 2 mole NaCl

0.352 mole Cl2 will produce 0.704 mole NaCl= 0.704×58.5=41.18 g NaCl.


Yield= 41.18/(29+25)

= 41.18/54

= 0.76 Or 76%




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