Inactive Tutor answered 11/28/21
Tutor
New to Wyzant
∫∫x2-y2dxdy=∫x3/3-xy2+Cdy=yx3/3-xy3/3+Cy=xy(x2-y2)/3+Cy
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asked 11/28/21Inactive Tutor answered 11/28/21
∫∫x2-y2dxdy=∫x3/3-xy2+Cdy=yx3/3-xy3/3+Cy=xy(x2-y2)/3+Cy
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