
Yefim S. answered 11/21/21
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dy/dt + 1/4y = 0; y(0) = - 8;
sY(s) + 8 + 1/4Y(s) = 0; Y(s) = - 8(s + 1/4); y(t) = L-1[- 8/(s + 1/4)] = - 8e-t/4
Sarah S.
asked 11/20/21-4 dy/dt - y = 0 y(0) = -8
I need to use Y for laplace transform of y
( ) = Y{0}
So Y = ( ) / (s - )
and y(t) = -8e^(-t/4)
Yefim S. answered 11/21/21
Math Tutor with Experience
dy/dt + 1/4y = 0; y(0) = - 8;
sY(s) + 8 + 1/4Y(s) = 0; Y(s) = - 8(s + 1/4); y(t) = L-1[- 8/(s + 1/4)] = - 8e-t/4
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