Nikolay M. answered • 08/30/21
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What does d^2y/dt^2 = 0 mean?
Find that it is zero at some point t or 0 everywhere in the domain?
Nikolay M.
Actually it is at a single point 0 only. I recommend the following. 1) plug y=0 and calculate y'(0)=dy/dt(0) = 3/5 (beware of y' y-prime) at t=0: y=0, y'=3/5 2) Differentiate find the second derivative (quotient rule + chain rule to get y') d^2y/dt^2 = (-4y'(5+4y) - 4y'(3-4y)) / (5+4y)^2 d^2y/dt^2(0) = (-4*3/5*(5 + 0) - 4 * 3/5 * (3 - 0)) / 5^2 = -96/25
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08/30/21
Nikolay M.
-96/125 (typo)
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08/30/21
Ed W.
Thank you I see my mistake
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08/30/21
Ed W.
Sorry it’s not supposed to have the equal sign. just d^2y/dt^2 (0). So I guess the whole domain08/30/21