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Question

Write the molecular equation and net ionic equation for the reaction of hydroiodic acid and potassium hydroxide. Include phases (states). Enter the formula for water as H2O . molecular equation: -> ⟶ net ionic equation: -> ⟶

Answer 1

Potassium hydroxide and hydroiodic acid are a strong base and a strong acid, respectively. So this means that both will completely dissociate into solution. The products of an acid-base reaction with strong acids and bases are always going to be water and a salt (which can either be soluble or insoluble). Check water solubility rules to determine whether or not the salt formed is water soluble.

Acids release protons (H⁺) and bases will release hydroxide anions (OH^-) when added to solution. These two ions will come together to form the water as a product.

Then we have an iodide anion (I^-) and a potassium cation (K⁺) remaining. These will combine together to form the salt. Salts containing group 1 metals are soluble and salts containing the halogens are soluble (there are exceptions, but K and I are not any of those exceptions).

So we will get the following molecular equation:

HI _(aq) + KOH _(aq) ----------> H₂O _(l) + KI _(aq)

To determine the net ionic equation, we must first write out an ionic equation to determine all the ions that form:

H⁺ _(aq) + I^-_(aq) + K⁺_(aq) + OH^-_(aq) --------> H₂O _(l) + K⁺_(aq) + I^-_(aq)

Using the ionic equation, you must cross out all of the spectator ions. The spectator ions are the ions that do not participate in the reaction. If an ion exists in the same state on both sides of the equation, it is a spectator ion and should be cancelled out. In our ionic equation, the iodide anions and potassium cations on both sides of the equation will cancel out since these are the spectator ions.

H⁺ _(aq) + I^-_(aq) + K⁺_(aq) + OH^-_(aq) --------> H₂O _(l) + K⁺_(aq) + I^-_(aq)

This leaves us the following net ionic equation:

H⁺_(aq) + OH^-_(aq) ---------> H₂O_(l)