please Answer this for me

Question

Calculate [ OH− ] for a solution where [H3O+]=0.00501 M . [OH−]= M

Answer 1

Concentration of [OH-}*{H3O+}= 1.0x10^-14

So now plug in your concentration given for hydronium and solve for Hydroxide concentration.

[OH-]*[0.00501]]= 1.0x10^-14

[OH-]= 1.0x10^-14/[0.00501]

[OH-] = 1.996x 10^-12 or if you want to round and keep sig figs correct you can say 2.00x 10^-12