Can someone please solve this

Question

A sealed container holding 0.0255 L of an ideal gas at 0.995 atm and 69 ∘C is placed into a refrigerator and cooled to 45 ∘C with no change in volume. Calculate the final pressure of the gas. 𝑃= atm

Answer 1

For this we can use an amended version of the ideal gas law in which

(P₁V₁)/T₁ = (P₂V₂)/T₂

where the left side of the equation is the initial conditions and the right side is the resulting conditions. Since there is no change in volume, we can exclude volume from our equation to get

P₁/T₁ = P₂/T₂

Since the equation is derived from the ideal gas law in which temperature is given in Kelvin, we'll convert our temperatures to Kelvin. Our initial 69ºC becomes 342.15 K and the final 45ºC becomes 318.15 K. Plugging into our equation, we get

0.995/342.15 = P₂/318.15

Solve for the final pressure (units are in atm since that's what we plugged in) to get:

P₂ = 0.925 atm