Can someone please solve this

Question

A sample of an ideal gas has a volume of 2.30 L at 279 K and 1.13 atm. Calculate the pressure when the volume is 1.64 L and the temperature is 303 K. 𝑃= atm

Answer 1

With ideal gas equations, one of the main ones you can use in order to keep with the law that energy cannot be destroyed but only transfered, and that with ideal gases the properties of one must translate to the properties iin some way to another, hence equations like P1V1=P2V2 and C1V1=C2V2.

PV=nrt is another ideal gas equation that can be used. You will use everything given here to solve for n and use the right R constant that takes these units into consideration. Then you will us that n, which is moles to solve for the pressure, which is what they are asking you when given new volume and temperature..

PV= nRt

solve for n

we use R constant 0.08205Latm/molK, because this is the R constant that takes into consideration the units provided.

1.13(2.30)= n0.08205*279

n= 1.13(2.30) / 0.08205*279

n= 2.599/ 22.89195

n = 0.1135 moles

now take this moles and plug it in to the same equation with the new values and solve for P or pressure.

new volume = 1.64 L new temp = 303K

PV=nRT

P(1.64)= 0.1135*0.08205*303

P= 0.1135*0.08205*303/ 1.64

P= 1.72 atm