Can someone please solve this question for me????

Question

Given the following equation:

Fe₂O₃ + 3 C  2 Fe  + 3 CO

How many grams of Fe2O3 are required to produce 9.01 grams of C? 

___________  g Fe2O3

Answer 1

Your problem is worded strangely. You are not creating C from Fe₂O₃ - they are both reactants. It makes more sense to ask how much Fe₂O₃ is required to create 9.01g of CO. For this problem, though, I will calculate how much Fe₂O₃ we will produce if we produced 9.01g of C.

We are given 9.01 g C, so let's see how many moles that is. Use stoichiometry with carbon's molecular weight to calculate:

9.01 g / 12.011 g/mol = 0.75 mol C

Notice that this is 3 molar equivalents. Think of it like the equation 3X = 0.75. We must figure out what x is so that we can apply it to the Fe₂O_3.

0.75 / 3 = 0.25 mol per molar equivalent

We create 1 molar equivalent of Fe₂O₃, which is 0.25 moles. From here we can calculate the g of Fe₂O_3.

0.25 mol * 159.69 g/mol = 42.42 g Fe₂O₃