Inactive Tutor answered 07/24/21
Tutor
New to Wyzant
∫01y∫0y+1xdx = 1/2∫01yx20y+1dy = 1/2∫01y(y + 1)2dy = 1/2∫01(y3 + 2y2 + y)dy = 1/2(y4/4 + 2y3/3 + y2/2)01 =
1/2(1/4 + 2/3 + 1/2) = 17/24
Rousser C.
asked 07/24/21Determine the integral of x y dx dy. Use inner limits=0 to (y + 1) and outer limits=0 to 1.
Inactive Tutor answered 07/24/21
∫01y∫0y+1xdx = 1/2∫01yx20y+1dy = 1/2∫01y(y + 1)2dy = 1/2∫01(y3 + 2y2 + y)dy = 1/2(y4/4 + 2y3/3 + y2/2)01 =
1/2(1/4 + 2/3 + 1/2) = 17/24
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