Yefim S. answered 07/22/21
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y' = - 2sin(2x).
Surface area S = 2π∫0π/6cos(2x)√1 + 4sin2(2x)dx = 3.755
Mary J.
asked 07/22/21Find the area of the surface obtained by rotating the curve y=cos(2x),0≤x≤(𝜋/6),about the 𝑥x-axis.
Yefim S. answered 07/22/21
Math Tutor with Experience
y' = - 2sin(2x).
Surface area S = 2π∫0π/6cos(2x)√1 + 4sin2(2x)dx = 3.755
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