Chemistry Question

Question

The rate of effusion of SO4 gas through a porous barrier is observed to be 4.56*10^-4 mol/h.

Under the same conditions, the rate of effusion of He gas would be mol/h.

________________________________________________________________________________________

A sample of SO2 gas is observed to effuse through a pourous barrier in 2.11 minutes. Under the same conditions, the same number of moles of an unknown gas requires 1.68 minutes to effuse through the same barrier.

The molar mass of the unknown gas is g/mol.

Answer 1

Part 2.

Use Graham's law of effusion Effusion rate for SO2 / Effusion rate of X = √ Mol mass X / Mol mass SO2.

In this case the time of effusion is inversely related to the effusion rate, so Graham's law becomes

Effusion time for SO2 / Effusion time for X = √ Mol mass SO2 / Mol mass X.

2.11 min / 1.68 = √ 64.1 / X solve for X by squaring both sides of equation.

1.577 = 64.1 / X X = 40.6 g /mole

As for part 1, I am not familiar with SO4 gas.