
Yefim S. answered 06/08/21
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dy/dx = (dy/dt)/(dx/dt) = 2a/(2at) = 1/t
d2y/dx2 = d/dx(1/t) = d/dt(1/t)·dt/dx = (- 1/t2)/(dx/dt) = (-1/t2)/(2at) = -1/(2at3)
Bright D.
asked 06/08/21If x=at^2 ,y=2at, find dy/dx and d^2y/dx^2 in terms of t
Yefim S. answered 06/08/21
Math Tutor with Experience
dy/dx = (dy/dt)/(dx/dt) = 2a/(2at) = 1/t
d2y/dx2 = d/dx(1/t) = d/dt(1/t)·dt/dx = (- 1/t2)/(dx/dt) = (-1/t2)/(2at) = -1/(2at3)
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