
Nasar N. answered 05/29/21
Tutor
5
(7)
Teaching is my patient
y=u^6 - 2u^3 +5u^-2
dy/du=6u5 -2(3u2) + 5(-2u-1)
dy/du= 6u5 -6u2 -10/u
Kaye K.
asked 05/28/21Find the derivative of y=u^6-2u^3+5/u^2
Nasar N. answered 05/29/21
Teaching is my patient
y=u^6 - 2u^3 +5u^-2
dy/du=6u5 -2(3u2) + 5(-2u-1)
dy/du= 6u5 -6u2 -10/u
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