Find the first derivative of z=x^3-xy^2+3y^2

Answer 1

Solution:-

We have to find the derivative of following

z = x3 - xy2 + 3y2

Differentiating the given function with respect to x.

z = d/dx ( x³ - xy² + 3y²)

= d/dx (x³) - d/dx (xy²) + d/dx (3y²)

= 3x² - y² + 0

Answer:- 3x² -y²