I will not solve these for you but I will tell you how to do them.
For inverse cosh: integrate by parts with u=cosh-1x, du=1/sqrt(x2-1), v=x, dv=1
The integral you get will need the substitution=t=x2-1.
For the rational fraction: you will need partial fractions with denominators x2, x2+2 and (x2+2)2
The first term is easy, the second term is an arcsin, and the third terms is integrable but messy (look it up in a short table)