In the balanced equation for the following, what is the correct molar coefficient for Li? Li (s) + I2 (s) --> LiI (s)

Answer 1

There are 2 iodine atoms on the reactant side and only 1 iodine atom on the product side. First balance the iodine by writing a coefficient of 2 in front of LiI.

Li + I₂ → 2 LiI

By placing a coefficient of 2 in front of LiI, there are now 2 Li atoms on the product side and only 1 atom on the reactant side. To balance, write a coefficient of 2 in front of Li on the reactant side.

2 Li + I₂ → 2 LiI

The above reaction is now balanced.