find *integral sign with 9 at the top and 1 at the bottom* (x-3)/square root of x dx

Answer 1

Re-write the integrand as sqrt(x)-[3/sqrt(x)].

The antiderivative is (2/3)x^3/2 - 6x^1/2

You plug in the limits of integration to get the answer.

P.S. Just to look "nice", you might have written your problem as: the integral from 1 to 9 of the integrand

(x-3) divided by the sqrt(x).