
Owen K.
asked 04/07/21*integral sign* (6w *square root* w) dw
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1 Expert Answer

Yefim S. answered 04/07/21
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5
(20)
Math Tutor with Experience
∫6w√wdw = 6∫w3/2dw = 6·2/5w5/2 + C = 12/5w2√w + C
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Paul M.
04/07/21