Jim B. answered • 03/04/15
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Since you have two points, first find the slope of the line.
Remember that there are three common forms for an equation of a line:
a) slope intercept form y = mx + b where m is the slope and b is the y intercept
b) standard form : Ax + By = c where A, B, and C are integers, A is non-negative
c) point slope (y - y1) = m(x - x1) where m is the slope of the line and (x1, y1) represent one point.
Since you have two points, find the slope, they you will have two points and the slope.
Select either point and write the equation in point slope format.
From point slope format, solve for y to put the equation in slope intercept form.
From slope intercept form y = mx + b, solve for b, then make sure that the coefficient of x is a non-negative integer.
Jim B.
Slope is rise/run or the change in y divided by the change in x,
(y2 - y1)
m=-----------
(x2 - x1)
(14 -12)
m = ---------
(6 - 4)
m = 2/2 =1 so the slope of this line is 1.
in point slope format, using slope is one and choosing the first point (4, 12)
y - 12 = 1(x -4)
to put this into y-intercept form, solve for y
a) use the distributive property : y - 12 = x -4
b) add 12 to both sides to isolate y: y = x + 8
this is in slope intercept form: y = mx + b, with the slope = 1 and y-intercept = 8
See graphs: http://hwmath.net/solutions/eq-line-4-12-6-14.jpg
Use algebra to put this into standard format Ax + By = C
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03/05/15
Jamison S.
03/04/15