The easiest way to establish a power series is to formulate a Taylor series. Since your initial conditions depend on x = 0, the series will be centered at this point. The series will be of the form
y = f(x) = f(0) + f'(0)x + f''(0)x2/2! + f'''(0)x3/3! + fiv(0)x4/4!.................
the first term is known, f(0) = a write the equation as y'' = -xy' - y
So,
y''(0) = -(0)(0) - (a) = - a
Then,
y''' = -y' - xy'' - y' then y'''(0) = -(0) - (0)(-a) - (0) = 0
Then,
yiv = -y'' -y'' - xy''' - y'' then yiv(0) = +2a - (0)(0) + a = 3a
Then,
yv = -4y''' - xyiv then yv(0) = -4(0) -(0)(-a) = 0
Then,
yvi = -5yiv - xyv then yvi = -5(3a) - (0)(0) = -15a
So, the first 4 terns would be
y = f(x) = a + (-a)x2/2! + (3a)x4/4! + (-15a)x6/6!