Straight-ahead u-substitution:
∫01[x/(x2+2)]dx u = x2 + 2 du = 2xdx. 1/2du = xdx
1/2 ∫23 [1/u]du = 1/2ln|u| ]23 = 1/2 (ln3 - ln2) ~ .2027...
Honey C.
asked • 03/09/21Evaluate the integral x dx/x^2+2 from 0 to 1
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