d/dx[√x] = 1/(2√x) so d/dx[∫...] = 1/(2√x) · (√x)√x = (√x)√x - 1 / 2 or .5x1/2(√x-1)
Avas A.
asked 03/08/21Use the Fundamental Theorem of Calculus to carry out the following differentiation:
Use the Fundamental Theorem of Calculus to carry out the following differentiation:
d ∫1√x tt dt= ?
dx
integral from 1 to sqrt x
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