If f(x) = integral 3 to x^2 t^4 dt, then f'(x) =?

Question

f(x) = ∫₃^{x^2} t⁴ dt, then what is f ' (x)= ?

Answer 1

f(x) = ∫₃^{x^2} t⁴ dt

From FTC, ∫_a^g(x)f(t)dt = f(g(x))g'(x)

g(x) = x²

f'(x) = (x²)⁴(2x) = 2x⁹