Inactive Tutor answered 03/04/21
Tutor
New to Wyzant
(1 + x) y' = 7x
y' = 7x/(1 + x)
y' = 7 - 7/(x + 1)
dy/dx = 7 - 7/(x + 1)
dy = [7 - 7/(x + 1)] dx
∫dy = ∫[7 - 7/(x + 1)] dx
y = 7x - 7ln(x + 1) + C
Efrain G.
asked 03/04/21Inactive Tutor answered 03/04/21
(1 + x) y' = 7x
y' = 7x/(1 + x)
y' = 7 - 7/(x + 1)
dy/dx = 7 - 7/(x + 1)
dy = [7 - 7/(x + 1)] dx
∫dy = ∫[7 - 7/(x + 1)] dx
y = 7x - 7ln(x + 1) + C
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