Inactive Tutor answered 03/03/21
Tutor
New to Wyzant
Surface area S = 2π∫01f(x)√1 +f'2(x)dx = 2π∫01(x3/3)(1 + x4)1/2dx = 2π/3·1/4(1 + x4)3/2·2/301 = π
π/9[23/2 - 1) = π(2√2 - 1)/9 = 0.638
Bashami S.
asked 03/03/21Can u guys find the surface area of y=(x^3)/3 rotated about x axis (0=<x=<1)
Inactive Tutor answered 03/03/21
Surface area S = 2π∫01f(x)√1 +f'2(x)dx = 2π∫01(x3/3)(1 + x4)1/2dx = 2π/3·1/4(1 + x4)3/2·2/301 = π
π/9[23/2 - 1) = π(2√2 - 1)/9 = 0.638
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