I think you want x = (4/√5)sint, then dx = (4/√5)costdt
∫√(16 - 5x2)dx = ∫√(16-16sin2t)(4/√5) cost dt
= (16/√5)∫√(1-sin2t) cost dt
= (16/√5)∫√cos2t cost dt
= (16/√5)∫cos2t dt
= (16/√5)∫[(1 + cos(2t))/2]dt
= (16/√5)[(1/2)t - (1/4)sin(2t)] + C
= (1/√5)[8t - 4sin(2t)] + C