CO2 formed from 17g of benzene

Question

Balanced equation of benzene

2C6H6 + 15O2 —> 12CO2 + 6H2O

I balanced the equation but I do not know how to determine how much CO2 is formed by the complete combustion of 17g of Benzene.

please show me ALL your work so I can learn. I can’t find an example similar to this online. I need to be able to see how my brain should be able to replicate.

Answer 1

From the balance equation you learn the mole ratio of C₆H₆ to CO₂ is 2:12

Covert grams of C₆H₆ to moles

17g C₆H₆ x (78g / 1 mole C₆H₆) = 0.2179 moles C₆H₆

find moles of CO₂ using mole ratio above

0.2179 moles C₆H₆ x (12 moles CO₂ / 2 moles C₆H₆) = 2.61 mole of CO₂

Convert moles back to grams

2.61 moles CO₂ x (44 g x 1 mole) = 114.84 g of CO₂