organic chemistry Please Help

Question

(6.17)    Write formulas for all possible dibromo products from the monobromination of the following compound. Which of the dibromo products would be optically active?

(R)-C₆H₅CHBrCH₂C₆H₅

2.    Draw all of the resonance forms of the following compound:

3.    (6.19) Rank the following radicals in order of increasing stability (least stable first):

Answer 1

Hi Will E.,

First of all, you should be aware that included images such as you furnished for these three problems are not openable by your prospective tutor helpers.

The first problem is therefore the only one attackable here.

Depending on the mechanism, the phenyl ring carbons or the alkane positions, may all be attacked by a bromination.

That covers a real mess of products! If Br #2 adds to the C with Br#1 on, that wouldn''t be optically active. And one of the two isomers for attack at the other alkane carbon will be optically active (R, R'); the other (R,S) won't be. The various brominations at the phenyl carbons won't affect the existing optical properties, since these attacks result in brominated phenyl positions, not breaking the resonance of the ring.

Hope that helps you ----

-- Cheers, --Mr. d.