A worker invested $26,000 into two accounts, one yielding 5% interest and the other yielding 12%. If he recieved a total of $1720 at the end of the year, how much did he invest at 5% ?

Question

A worker invested $26,000 into two accounts, one yielding 5% interest and the other yielding 12%. If he recieved a total of $1720 at the end of the year, how much did he invest at 5% ?

Answer 1

let's separate the 26000 into two pieces

1) x

2)26000-x

x will represent a certain value between 0 and 26000. Once you know x you can subtract it from 26000 to determine the other amount between 0 and 26000.

x(.05)+(26000-x)(.12)=1720

.05x+3120-.12x=1720

-.07x=-1400

x=20000

x equals 20000 and that value is the one invested at 5 percent while 26000-20000=6000 is the amount invested at 12 percent.

Answer 2

0.05x + 0.12(26000 - x) = 1720

Can you solve for x and answr?