g(x) = (sec(ln(x))) / (tan^2(x))

Question

 Differentiation. i need help with this problem.

Answer 1

g(x) = (sec(ln(x))) / (tan²(x))

g'(x) = [(1/x)(sec(ln(x)))(tan(ln(x))(tan²(x)) -  (sec(ln(x)))2(tan(x))(sec²(x))]/(tan⁴(x))

g'(x) = (sec(ln(x)))[(1/x)(tan(ln(x))(tan(x)) - (2(sec²(x))]/(tan³(x))